18n^2+19n=-17n

Solution for 18n^2+19n=-17n equation:

18n^2+19n=-17n

We move all terms to the left:

18n^2+19n-(-17n)=0

We get rid of parentheses

18n^2+19n+17n=0

We add all the numbers together, and all the variables

18n^2+36n=0

a = 18; b = 36; c = 0;
Δ = b2-4ac
Δ = 362-4·18·0
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-36}{2*18}=\frac{-72}{36}
=-2
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+36}{2*18}=\frac{0}{36}
=0
$